If p times the pth term of an AP is equal to q times the qth term (p\neq q), then what is the (p+q)th term equal to?
- A. 0 ✓
- B. p+q
- C. pq
- D. pq(p+q)
Correct Answer: A. 0
Explanation
Given p[a + (p-1)d] = q[a + (q-1)d], rearranging yields a(p-q) + d(p^2 - q^2 - p + q) = 0. Factoring out (p-q) leaves a + (p+q-1)d = 0, which is exactly the expression for the (p+q)th term.
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