How many terms are identical in the two APs 19, 21, 23, \dots up to 110 terms and 19, 22, 25, 28, \dots up to 75 terms?

  1. A. 35
  2. B. 36
  3. C. 37
  4. D. 38

Correct Answer: C. 37

Explanation

First AP: d_1 = 2, max term = 19 + 109 \times 2 = 237. Second AP: d_2 = 3, max term = 19 + 74 \times 3 = 241. The identical terms form a new AP with a = 19 and common difference d = \text{lcm}(2, 3) = 6. We need 19 + 6(n - 1) \leq 237 \implies 6(n - 1) \leq 218 \implies n - 1 \leq 36.33. Therefore, n = 37.

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