Let p, q and r be three unequal numbers such that p, q and r are in AP. If (q - p), (r - q) and p are in GP, then (p + q) : (q + r) : (r + p) equals
- A. 1 : 2 : 3
- B. 3 : 4 : 5
- C. 3 : 5 : 4 ✓
- D. 1 : 3 : 2
Correct Answer: C. 3 : 5 : 4
Explanation
Since p, q, r are in AP, their common difference is d. Given d, d, p are in GP, p = d. Thus q = 2d, r = 3d, leading to the ratio 3:5:4.
Related questions on Algebra
- How many four-digit natural numbers are there such that <strong>ALL</strong> of the digits are odd?
- What is \sum_{r=0}^{n}2^{r}C(n,r) equal to ?
- If different permutations of the letters of the word 'MATHEMATICS' are listed as in a dictionary, how many words (with or without meaning) a...
- Consider the following statements : 1. If f is the subset of Z\times Z defined by f=\{(xy,x-y);x,y\in Z\}, then f is a function from...
- For how many quadratic equations, the sum of roots is equal to the product of roots?