What is the smallest positive \( x \) satisfying \( \log_{\sin x} \cos x + \log_{\cos x} \sin x = 2 \) ?

  1. A. \frac{\pi}{2}
  2. B. \frac{\pi}{3}
  3. C. \frac{\pi}{4}
  4. D. \frac{\pi}{6}

Correct Answer: C. \frac{\pi}{4}

Explanation

Let y = \log_{\sin x} \cos x. The equation becomes y + 1/y = 2, which gives y = 1. So \log_{\sin x} \cos x = 1, leading to \sin x = \cos x. The smallest positive x satisfying this is \pi/4.

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